# Line slope calculator 5x-2y=-5

**Straight line given by points A[1; 5] and B[3; 10]**

## Calculation:

**Slope-intercept form of line:**y = 2.5x+2.5

**Canonical form of the line equation:**5x-2y+5 = 0

**Parametric form of the line equation:**

x = 2t+1

y = 5t+5 ; t ∈ R

**Slope:**m = 2.5

**Slope angle of line: φ =**68°11'55″ = 1.1903 rad

**X intercept:**x

_{0}= -1

**Y intercept:**y

_{0}= q = 2.5

**Distance line from the origin:**d

_{0}= 0.9285

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; 5)

**Normal vector: n =**(5; -2)

**Midpoint of the segment AB: M =**[2; 7.5]

**Perpendicular Bisector equation:**2x+5y-41.5 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (3; 10) ; |OB| = 10.4403**

**Scalar product OA .OB = 53**

**Angle ∠ AOB = 5°23'22″ = 0.0941 rad**